(y^4+5x^2)+(6x^2-3y^4)=0

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Solution for (y^4+5x^2)+(6x^2-3y^4)=0 equation:


Simplifying
(y4 + 5x2) + (6x2 + -3y4) = 0

Reorder the terms:
(5x2 + y4) + (6x2 + -3y4) = 0

Remove parenthesis around (5x2 + y4)
5x2 + y4 + (6x2 + -3y4) = 0

Remove parenthesis around (6x2 + -3y4)
5x2 + y4 + 6x2 + -3y4 = 0

Reorder the terms:
5x2 + 6x2 + y4 + -3y4 = 0

Combine like terms: 5x2 + 6x2 = 11x2
11x2 + y4 + -3y4 = 0

Combine like terms: y4 + -3y4 = -2y4
11x2 + -2y4 = 0

Solving
11x2 + -2y4 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2y4' to each side of the equation.
11x2 + -2y4 + 2y4 = 0 + 2y4

Combine like terms: -2y4 + 2y4 = 0
11x2 + 0 = 0 + 2y4
11x2 = 0 + 2y4
Remove the zero:
11x2 = 2y4

Divide each side by '11'.
x2 = 0.1818181818y4

Simplifying
x2 = 0.1818181818y4

Take the square root of each side:
x = {-0.426401433y2, 0.426401433y2}

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